Question

when writing binary data, we often put a space between each byte to make it easier for humans to read. consider this binary data: 010101011101001011000000 which choice puts a space after each byte? choose 1 answer: a 01010101 11010010 11000000 b 010101011101 001011000000 c 0101 0101 1101 0010 1100 0000 d 01 01 01 01 11 01 00 10 11 00 00 00

Explanation:

Step1: Recall a byte has 8 bits.

The original binary data: \(010101011101001011000000\) (wait, let's count the bits. Wait, the given data is \(010101011101001011000000\)? Wait, no, let's check the length. Wait, the options: let's split the original data into 8 - bit chunks.

Original data: \(01010101\) (8 bits), \(11010010\) (8 bits), \(11000000\) (wait, no, wait the original data is \(010101011101001011000000\)? Wait, let's count the number of bits. Let's see:

Option A: \(01010101\) (8), \(11010010\) (8), \(11000000\) (wait, no, \(11000000\) is 8? Wait, \(11000000\) is 8 bits. Wait, original data: let's write the original data as a string: "010101011101001011000000". Let's count the characters: 8 + 8+ 8? Wait, 8*3 = 24. Let's count: "01010101" (8) + "11010010" (8) + "11000000" (8) = 24. Yes. So splitting into 8 - bit chunks: first 8: 01010101, next 8: 11010010, next 8: 11000000. Which matches option A.

Step2: Check other options.

Option B: chunks are not 8 bits. Option C: chunks are 4 bits. Option D: chunks are 2 bits. So only option A has 8 - bit (1 byte) chunks.

Answer:

A. 01010101 11010010 11000000