Question

when the useful energy output of a simple machine is 100 j, and the total energy input is 200 j, the efficiency is ______. view available hint(s) 75 percent 50 percent 100 percent 200 percent submit provide feedback

Explanation:

Step1: Recall efficiency formula

The formula for the efficiency (\(\eta\)) of a machine is \(\eta=\frac{\text{Useful Energy Output}}{\text{Total Energy Input}}\times100\%\)

Step2: Substitute values

Given useful energy output \( = 100\space J\) and total energy input \(= 200\space J\). Substitute into the formula: \(\eta=\frac{100}{200}\times 100\%\)

Step3: Calculate the value

First, \(\frac{100}{200}=0.5\), then \(0.5\times100\% = 50\%\)

Answer:

50 percent (corresponding to the option "50 percent")