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when ednas phone is fully charged, it can operate for up to 18 hours be…

Question

when ednas phone is fully charged, it can operate for up to 18 hours before running out of battery. it has been 6 hours since ednas phone was fully charged. let x represent how many more hours ednas phone can operate without running out of battery. which inequality describes the problem? 6 + x < 18 6 + x ≤ 18 solve the inequality. then, complete the sentence to describe the solution. ednas phone can operate for to more hours without

Explanation:

Part 1: Choosing the Correct Inequality
Brief Explanations

The total operating time (used time + remaining time) should be at most the maximum battery life (18 hours). So \( 6 + x \) (6 hours used + \( x \) hours remaining) must be less than or equal to 18. Thus, \( 6 + x \leq 18 \) is correct.

Step 1: Subtract 6 from both sides

To solve \( 6 + x \leq 18 \), subtract 6 from each side:
\( 6 + x - 6 \leq 18 - 6 \)
Simplify to get \( x \leq 12 \). Since time can't be negative, \( x \geq 0 \) (implicitly, as it's hours remaining). So the solution is \( 0 \leq x \leq 12 \).

Answer:

\( 6 + x \leq 18 \)

Part 2: Solving the Inequality