Question

whats the inverse of (f(x) = 3x^3 - 4)?

a) (f^{-1}(x) = 3x + 4)
b) (f^{-1}(x) = \frac{x+4}{3})
c) (f^{-1}(x) = sqrt{\frac{x+4}{3}})
d) (f^{-1}(x) = sqrt3{\frac{x+4}{3}})

question 17 (5 points)
given that (f(x) = 4x + 5) and (g(x) = x^2 - 2x - 2), find ((f + g)(x)).

a) ((f + g)(x) = x^2 + 2x + 3)
b) ((f + g)(x) = -x^2 + 6x + 7)
c) ((f + g)(x) = -x^2 + 2x - 7)
d) ((f + g)(x) = x^2 + 6x + 3)

question 18 (5 points)
simplify: (3sqrt{28} + 4sqrt{7} + 2sqrt{32})

a) (10sqrt{7} + 8sqrt{2})
b) (10sqrt{7} - sqrt{2})
c) (10sqrt{7} + 5sqrt{2})
d) (14sqrt{7} + 5sqrt{2})

Explanation:

Find the inverse of the first function

$$
LATEXBLOCK0
$$

Find the sum of the functions for Question 17

$$
LATEXBLOCK1
$$

Simplify the radical expression for Question 18

$$
LATEXBLOCK2
$$

Answer:

Question 1

• A) \(f^{-1}(x) = 3x + 4\)
• B) \(f^{-1}(x) = \frac{x+4}{3}\)
• C) \(f^{-1}(x) = \sqrt{\frac{x+4}{3}}\)
• D) \(f^{-1}(x) = \sqrt[3]{\frac{x+4}{3}}\) (Correct answer)

Question 17

• A) \((f + g)(x) = x^2 + 2x + 3\) (Correct answer)
• B) \((f + g)(x) = -x^2 + 6x + 7\)
• C) \((f + g)(x) = -x^2 + 2x - 7\)
• D) \((f + g)(x) = x^2 + 6x + 3\)

Question 18

• A) \(10\sqrt{7} + 8\sqrt{2}\) (Correct answer)
• B) \(10\sqrt{7} - \sqrt{2}\)
• C) \(10\sqrt{7} + 5\sqrt{2}\)
• D) \(14\sqrt{7} + 5\sqrt{2}\)