Question

what are the zeros of this quadratic function?
$f(x) = (x - 7)(x + 8)$
a. $x = -7$ and $x = 8$
b. $x = 0$ and $x = 7$
c. $x = 0$ and $x = -8$
d. $x = 7$ and $x = -8$

Explanation:

Step1: Set function equal to 0

$f(x) = (x-7)(x+8) = 0$

Step2: Solve first linear factor

$x-7=0 \implies x=7$

Step3: Solve second linear factor

$x+8=0 \implies x=-8$

Answer:

D. $x = 7$ and $x = -8$