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Question
what value of \\(n\\) makes the equation true?
\\((2x^9y^n)(4x^2y^{10}) = 8x^{11}y^{20}\\)
1
30
10
2
Simplify the left side of the equation
$$
(2x^9y^n)(4x^2y^{10}) = (2 \cdot 4)(x^9 \cdot x^2)(y^n \cdot y^{10}) = 8x^{11}y^{n+10}
$$
Equate the exponents of y
$$
y^{n+10} = y^{20} \implies n + 10 = 20
$$
Solve for n
$$
n = 10
$$
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