Question

what is the value of charges after the following code has been executed? <img src=\test_images/f167g1lg1_r.jpg\ alt=\double charges, rate = 7.00; int time = 180; charges = time <= 119 ? rate 2 : time / 60.0 rate;\ style=\vertical-align: -4.0px;\ />

○ 7.00
○ 14.00
○ 21.00
○ 28.00

Explanation:

Step1: Analyze the ternary operator condition

The condition is time <= 119. Given time = 180, we check if \(180 \leq 119\). This is false.

Step2: Evaluate the else part of the ternary operator

The else part is time / 60.0 * rate. Substitute time = 180 and rate = 7.00:
First, calculate \( \frac{180}{60.0} = 3.0 \). Then multiply by rate: \( 3.0 * 7.00 = 21.00 \).

Answer:

21.00