Question

what type of decay is taking place in this equation? 212 83 bi → 4 2 he + 208 81 ti gamma beta sigma alpha

Explanation:

Alpha decay is a type of radioactive decay where an atomic nucleus emits an alpha particle ($^{4}_{2}\text{He}$). In the given equation, $^{212}_{83}\text{Bi}$ emits $^{4}_{2}\text{He}$ to form $^{208}_{81}\text{Tl}$. This matches the characteristics of alpha decay.

Answer:

alpha