Question

what is the sum?
$2\frac{7}{8} + 4\frac{3}{8}$
$\bigcirc\\ 7\frac{2}{8}$
$\bigcirc\\ 5\frac{4}{8}$
$\bigcirc\\ 8\frac{10}{8}$
$\bigcirc\\ 6\frac{2}{8}$

Explanation:

Step1: Add whole numbers and fractions separately

Whole numbers: \(2 + 4 = 6\)
Fractions: \(\frac{7}{8} + \frac{3}{8} = \frac{7 + 3}{8} = \frac{10}{8}\)

Step2: Simplify the fraction

\(\frac{10}{8} = 1\frac{2}{8}\) (since \(10\div8 = 1\) with remainder \(2\))

Step3: Add the result from step1 and step2

\(6 + 1\frac{2}{8} = 7\frac{2}{8}\)? Wait, no, wait. Wait, original whole numbers: \(2 + 4 = 6\), fraction sum: \(\frac{7 + 3}{8}=\frac{10}{8}=1\frac{2}{8}\). Then \(6 + 1\frac{2}{8}=7\frac{2}{8}\)? But wait, the options have \(7\frac{2}{8}\) as an option. Wait, but let's check again. Wait, \(2\frac{7}{8}+4\frac{3}{8}\): add the whole parts \(2 + 4 = 6\), add the fractional parts \(\frac{7}{8}+\frac{3}{8}=\frac{10}{8}=1\frac{2}{8}\). Then \(6 + 1\frac{2}{8}=7\frac{2}{8}\). But the selected option is \(6\frac{2}{8}\), which is wrong. Wait, maybe I made a mistake. Wait, no: \(2\frac{7}{8}+4\frac{3}{8}\): \(2 + 4 = 6\), \(\frac{7}{8}+\frac{3}{8}=\frac{10}{8}=1\frac{2}{8}\). So \(6 + 1\frac{2}{8}=7\frac{2}{8}\). So the correct answer should be \(7\frac{2}{8}\), which is option A. But the selected option in the image is wrong. Wait, maybe the problem is misprinted? Wait, no, wait: \(2\frac{7}{8}+4\frac{3}{8}\): \(2 + 4 = 6\), \(\frac{7 + 3}{8}=\frac{10}{8}=1\frac{2}{8}\), so \(6 + 1\frac{2}{8}=7\frac{2}{8}\). So the correct answer is \(7\frac{2}{8}\), which is the first option.

Answer:

A. \(7\frac{2}{8}\)