Question

what are the solution(s) to the quadratic equation $9x^2 = 4$?
\\(\bigcirc\\) $x = \frac{4}{9}$ and $x = -\frac{4}{9}$
\\(\bigcirc\\) $x = \frac{2}{3}$ and $x = -\frac{2}{3}$
\\(\bigcirc\\) $x = \frac{3}{2}$ and $x = -\frac{3}{2}$
\\(\bigcirc\\) no real solution

Explanation:

Step1: Isolate $x^2$

Divide both sides by 9: $x^2 = \frac{4}{9}$

Step2: Take square roots

$x = \pm\sqrt{\frac{4}{9}} = \pm\frac{2}{3}$

Answer:

B. $x = \frac{2}{3}$ and $x = -\frac{2}{3}$