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Question
what is the quotient?
\\(\frac{t + 3}{t + 4} \div (t^2 + 7t + 12)\\)
- \\((t + 3)^2\\)
- \\((t + 4)^2\\)
- \\(\frac{1}{(t + 4)^2}\\)
- \\(\frac{1}{(t + 3)^2}\\)
Factor the quadratic expression
$$
t^2 + 7t + 12 = (t + 3)(t + 4)
$$
Rewrite the division as multiplication by the reciprocal
$$
\frac{t + 3}{t + 4} \div (t^2 + 7t + 12) = \frac{t + 3}{t + 4} \cdot \frac{1}{(t + 3)(t + 4)}
$$
Simplify the expression
$$
\frac{t + 3}{(t + 4)(t + 3)(t + 4)} = \frac{1}{(t + 4)^2} \quad (t
eq -3)
$$
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- (A) \((t + 3)^2\)
- (B) \((t + 4)^2\)
- (C) \(\frac{1}{(t + 4)^2}\) (Correct answer)
- (D) \(\frac{1}{(t + 3)^2}\)