Question

what is the net force acting on the box? what direction will it move? a. 10 n; to the right b. 0 n; it will not move c. 50 n; to the right d. 90 n; to the left

Explanation:

Step1: Calculate net - force in horizontal direction

Net force $F_{net}=F_{right}-F_{left}$. The force to the right is $F_{right} = 50N$, and the forces to the left are $F_{left1}=10N$ and $F_{left2}=30N$. So $F_{left}=10 + 30=40N$. Then $F_{net}=50-(10 + 30)=10N$.

Step2: Determine the direction of motion

Since $F_{net}=10N>0$, the net - force is in the direction of the larger force. The larger force is to the right, so the box will move to the right.

Answer:

A. 10 N; to the right