Question

1. what happens to the slope of the i-v curve for larger resistors?

Explanation:

The \( I\text{-}V \) curve for a resistor follows Ohm's law \( I = \frac{V}{R} \), so the slope of the \( I\text{-}V \) curve (where \( I \) is on the y - axis and \( V \) is on the x - axis) is \( \frac{1}{R} \). For larger resistors (\( R \) increases), the value of \( \frac{1}{R} \) decreases. So the slope of the \( I\text{-}V \) curve decreases (becomes smaller or flatter).

Answer:

The slope of the \( I\text{-}V \) curve (where \( I \) is the current and \( V \) is the voltage) for a resistor is given by \( \frac{1}{R} \) (from \( I=\frac{V}{R} \), in the form \( y = mx + c \) with \( y = I \), \( x = V \), \( m=\frac{1}{R} \), \( c = 0 \)). As the resistance \( R \) increases, the value of \( \frac{1}{R} \) (the slope) decreases. So the slope of the \( I\text{-}V \) curve becomes smaller (the curve becomes flatter) for larger resistors.