Question

1. what is the equation for coulombs law?
2. how many electrons is one coulomb?

Explanation:

Coulomb's Law describes the electrostatic force between two point - charges. The formula is \( F = k\frac{q_1q_2}{r^{2}}\), where \( F\) is the electrostatic force, \( k\) is Coulomb's constant (\( k=\frac{1}{4\pi\epsilon_0}\approx9\times 10^{9}\ N\cdot m^{2}/C^{2}\)), \( q_1\) and \( q_2\) are the magnitudes of the two charges, and \( r\) is the distance between them.

One Coulomb of charge is related to the charge of an electron (\( e=- 1.6\times10^{-19}\ C\)). Using the formula \( Q = ne\) (where \( Q\) is the total charge, \( n\) is the number of electrons, and \( e\) is the charge of a single electron), we can solve for \( n\). Rearranging gives \( n=\frac{Q}{e}\). Substituting \( Q = 1\ C\) and \( e=1.6\times 10^{-19}\ C\), we get \( n=\frac{1}{1.6\times 10^{-19}} = 6.25\times 10^{18}\) electrons.

Answer:

1. The equation for Coulomb's Law is \( F = k\frac{q_1q_2}{r^{2}}\).
2. One Coulomb is equal to \( 6.25\times 10^{18}\) electrons.