Question

what ensures the viability of one gamete in oogenesis?
the viable daughter cell goes through cell death.
the elimination of non - viable daughter cells through cell death.
the viable daughter cell absorbs organelles and resources from the three non - viable daughter cells.
the fusion of genetic material from the viable daughter cell to the non - viable daughter cells.

Explanation:

During oogenesis, one primary oocyte undergoes meiosis. In meiosis I, a secondary oocyte (viable) and a polar body (non - viable) are formed. In meiosis II, the secondary oocyte forms an ovum (viable) and another polar body. The non - viable polar bodies (daughters of meiosis) undergo cell death (apoptosis). This elimination of non - viable daughter cells (polar bodies) through cell death ensures that the resources are concentrated in the single viable gamete (ovum).

• The first option is incorrect because the viable daughter cell (ovum) does not go through cell death.
• The third option is incorrect as there is no absorption of organelles and resources from non - viable cells by the viable cell in the context of ensuring its viability in the standard oogenesis process.
• The fourth option is incorrect as there is no fusion of genetic material from the viable to non - viable cells.

Answer:

The elimination of non - viable daughter cells through cell death.