Question

what is the density of the cube below if the mass is 24g? h = 2cm w = 2cm l = 3cm

Explanation:

Step1: Calculate the volume of the cube

The volume \( V \) of a rectangular prism (assuming the cube - like shape is a rectangular prism) is given by the formula \( V = L\times W\times H \).
Substituting \( L = 3\mathrm{cm}\), \(W = 2\mathrm{cm}\), and \(H = 2\mathrm{cm}\) into the formula:
\( V=3\times2\times 2\)
\( V = 12\mathrm{cm}^3\)

Step2: Calculate the density

The density \(
ho\) is given by the formula \(
ho=\frac{m}{V}\), where \(m\) is the mass and \(V\) is the volume.
Given \(m = 24\mathrm{g}\) and \(V = 12\mathrm{cm}^3\)
\(
ho=\frac{24}{12}\)
\(
ho = 2\mathrm{g/cm}^3\)

Answer:

\(2\mathrm{g/cm}^3\)