Question

using levers to measure ke in the example pictured, the soda bottle would act as the . the kinetic energy of the soda bottle will be converted into the of the beanbag. the higher the beanbag rises, the greater the .

Explanation:

First Blank:

In a lever system, the object that applies force (the effort or the load? Wait, here the soda bottle is falling, so it's the load? No, wait, in a lever, the "effort" is what we apply, but here the soda bottle's weight is the force causing the lever to move. Wait, actually, in a lever setup like a seesaw, the object that is the "weight" or the force - applying object (the one that falls) is the "load" or more accurately, the "effort" in terms of force? Wait, no. Let's think about levers. The part of the lever where the force is applied is the effort arm, and the load is what is being lifted. But in this case, the soda bottle is the one that has kinetic energy (when it falls) and it's the force - applying object on the lever. So it acts as the "effort" or the "weight" but more precisely, in terms of the lever components, the soda bottle is the "weight" or the "load" that provides the force to move the lever, which then lifts the beanbag. Wait, actually, in a lever, the "effort" is the force applied to move the load. But here, the soda bottle is the object that has kinetic energy (from falling) and when it hits the lever, it applies a force. So it acts as the "effort" or the "weight" (the force - applying mass). But more accurately, in the context of using a lever to measure kinetic energy, the soda bottle is the "weight" or the "mass" that provides the force, but actually, the correct term here is that the soda bottle acts as the "effort" or the "load" but in the context of energy transfer, the soda bottle's kinetic energy is transferred. Wait, no, let's recall: in a lever, the input force is from the soda bottle (when it falls, it has KE and applies a force to the lever). So the soda bottle acts as the "effort" (the force - applying object) or the "weight" (the mass that provides the force). But the standard term here, in a lever setup for this experiment, the soda bottle is the "weight" or the "mass" that is used to apply force, so it acts as the "effort" or the "load"? Wait, maybe the correct term is "weight" or "mass", but actually, in the lever, the part where the force is applied is the "effort" side. So the soda bottle is on the effort side, so it acts as the "effort" or the "weight" (the object providing the force). But the more accurate term here, in the context of the lever, the soda bottle is the "weight" (the mass) that is used to create a torque on the lever. So the first blank: the soda bottle would act as the "weight" (or "mass" or "effort force provider", but more likely "weight" or "load"). Wait, no, let's think about the lever components. The lever has a fulcrum, effort, and load. The effort is the force we apply, the load is what we lift. But in this case, the soda bottle is the one that is falling (so we can consider its kinetic energy), and it's applying a force to the lever (effort), which then lifts the beanbag (load). So the soda bottle acts as the "effort" (the force - applying object) or the "weight" (the mass that provides the force). So the first blank: "weight" (or "mass" or "effort").

Second Blank:

Kinetic energy (KE) of the soda bottle will be converted into what energy of the beanbag? When the lever lifts the beanbag, the beanbag gains height, so its potential energy (specifically gravitational potential energy) increases. So the KE of the soda bottle is converted into the "potential energy" (or "gravitational potential energy") of the beanbag.

Third Blank:

The higher the beanbag rises, the greater the potential energy (since $PE = mgh$, and $h$ is height). Since the potential energy of the beanbag comes from the kinetic energy of the soda bottle, a greater height means a greater potential energy, which implies a greater initial kinetic energy of the soda bottle. So the higher the beanbag rises, the greater the "kinetic energy" (of the soda bottle) or the "potential energy" (of the beanbag). But since the question is about what is greater, and the beanbag's height is related to the KE of the soda bottle, the higher the beanbag rises, the greater the "kinetic energy" (of the soda bottle) or the "potential energy" (of the beanbag). But more precisely, since the KE of the soda bottle is converted to PE of the beanbag, the higher the beanbag (greater PE), the greater the initial KE of the soda bottle. So the third blank: "kinetic energy" (of the soda bottle) or "potential energy" (of the beanbag). But in the context of the question, it's asking "the greater the ____", and since the beanbag's rise is due to the KE of the soda bottle, the higher it rises, the greater the KE of the soda bottle (or the PE of the beanbag). But likely, the answer is "kinetic energy" (of the soda bottle) or "potential energy" (of the beanbag). But let's check:

1. First blank: The soda bottle acts as the "weight" (or "mass" or "effort") - in the lever, the object that provides the force (the effort force) is the soda bottle, so it's the "weight" (the mass) or "effort".
2. Second blank: KE of soda bottle is converted to "potential energy" (gravitational potential energy) of the beanbag.
3. Third blank: The higher the beanbag rises, the greater the "kinetic energy" (of the soda bottle) (since more KE is needed to lift it higher) or the "potential energy" (of the beanbag). But since the PE of the beanbag is $mgh$, higher $h$ means higher PE, which comes from higher KE of the soda bottle. So the third blank is "kinetic energy" (of the soda bottle) or "potential energy" (of the beanbag). But likely, the intended answers are:

First blank: weight (or mass, or effort)

Second blank: potential energy (or gravitational potential energy)

Third blank: kinetic energy (of the soda bottle) or potential energy (of the beanbag)

But to be precise:

1. In the lever, the soda bottle is the "weight" (the mass that applies a force to the lever, causing it to rotate and lift the beanbag). So first blank: weight.

1. The kinetic energy of the soda bottle (when it falls and hits the lever) is converted into the potential energy (specifically gravitational potential energy, since the beanbag is lifted to a height) of the beanbag. So second blank: potential energy.

1. The higher the beanbag rises, the greater the potential energy it has, which means the initial kinetic energy of the soda bottle was greater (since energy is conserved, ignoring losses). So the higher the beanbag rises, the greater the "kinetic energy" (of the soda bottle) or the "potential energy" (of the beanbag). But since the question is phrased as "the greater the ____", and the context is measuring KE, the answer is that the higher the beanbag rises, the greater the "kinetic energy" (of the soda bottle).

Answer:

s:

1. First blank: weight (or mass, effort)
2. Second blank: potential energy (or gravitational potential energy)
3. Third blank: kinetic energy (of the soda bottle)