Question

using the axis of symmetry, find the vertex for the quadratic function.

\\f(x) = x^2 - 6x + 8\\

(?, )

hint: the formula for the axis of symmetry is \\(x = \frac{-b}{2a}\\)

Explanation:

Identify coefficients

Using the Quadratic Functions knowledge point

$$
LATEXBLOCK0
$$

Calculate axis of symmetry

Using the Axis of Symmetry knowledge point

$$ x = -\frac{b}{2a} = -\frac{-6}{2(1)} = 3 $$

Find vertex y-coordinate

Using the Parabola Vertex Identification knowledge point

$$
LATEXBLOCK1
$$

State vertex coordinates

Using the Parabola Vertex Identification knowledge point

$$ (h, k) = (3, -1) $$

Answer:

Using the axis of symmetry, find the vertex for the quadratic function.
\(f(x) = x^2 - 6x + 8\)
(<blank>3</blank>, <blank>-1</blank>)