Question

use the point - slope formula to write an equation of the line that passes through (-1, 1.4) and (-1.6, -1.9). write the answer in slope - intercept form (if possible). the equation of the line is.

Explanation:

Step1: Calculate the slope

The slope formula is $m=\frac{y_2-y_1}{x_2-x_1}$. Let $(x_1,y_1)=(-1,1.4)$ and $(x_2,y_2)=(-1.6,-1.9)$.
$m=\frac{-1.9-1.4}{-1.6-(-1)}=\frac{-3.3}{-0.6}=5.5$

Step2: Apply point-slope formula

Point-slope form: $y-y_1=m(x-x_1)$. Use $(x_1,y_1)=(-1,1.4)$ and $m=5.5$.
$y-1.4=5.5(x-(-1))$
$y-1.4=5.5(x+1)$

Step3: Convert to slope-intercept form

Expand and isolate $y$.
$y-1.4=5.5x+5.5$
$y=5.5x+5.5+1.4$
$y=5.5x+6.9$

Answer:

$y=5.5x+6.9$