Question

unit 6 sol review

1. if $f(x) = \frac{4x - 3}{5}$,

6a find $f(2)$
$f(2) = 1$
5 great job!
6b find $f(-4)$
$f(-4) = $ enter your next step here

Explanation:

Step1: Substitute \( x = -4 \) into the function \( f(x) \)

We have the function \( f(x)=\frac{4x - 3}{5} \). Substitute \( x=-4 \) into it, so we get \( f(-4)=\frac{4\times(-4)-3}{5} \).

Step2: Calculate the numerator

First, calculate the numerator \( 4\times(-4)-3 \). \( 4\times(-4)=-16 \), then \( -16 - 3=-19 \). So now the function becomes \( f(-4)=\frac{-19}{5} \).

Step3: Simplify the fraction

\( \frac{-19}{5}=-3.8 \) or we can write it as \( -\frac{19}{5} \).

Answer:

\( -\frac{19}{5} \) (or -3.8)