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unit 3: small engine mechanics - division worksheet (engine parts) dire…

Question

unit 3: small engine mechanics - division worksheet (engine parts)
directions: solve each problem. show all steps. use complete sentences to explain your reasoning.
division problems

  1. a mechanic has 72 piston rings. if each engine requires 6 piston rings, how many engines can be repaired? the piston ring was 72 and the engine required 6 pistons and how many could get repaired two piston rings.
  2. a shipment contains 144 valves. if these are packed equally into 12 boxes, how many valves are in each box? the 12
  3. a shop orders 96 crankshaft bearings. if they are divided equally among 8 mechanics, how many bearings does each mechanic receive? 12
  4. a shipment of 180 camshaft bearings must be divided into sets of 15 for storage. how many sets can be made? 36
  5. a shop has 120 air filters. if each repair job uses 4 air filters, how many jobs can be completed? 30
  6. a mechanic has 200 quarts of engine oil. if he uses 10 quarts per day, how many days will the oil last? 20

Explanation:

Step1: Identify the division - based relationship

To find the number of a certain entity, we divide the total quantity of a resource by the quantity of the resource required per entity.

Step2: Solve problem 1

We have 72 piston - rings and each engine requires 6 piston - rings. The number of engines that can be repaired is calculated as $\frac{72}{6}=12$.

Step3: Solve problem 2

There are 144 valves and 12 boxes. The number of valves in each box is $\frac{144}{12}=12$.

Step4: Solve problem 3

There are 96 crankshaft bearings and 8 mechanics. Each mechanic receives $\frac{96}{8}=12$ bearings.

Step5: Solve problem 4

There are 180 camshaft bearings and we need to make sets of 15. The number of sets is $\frac{180}{15}=12$.

Step6: Solve problem 5

There are 120 air - filters and each repair job uses 4 air - filters. The number of jobs is $\frac{120}{4}=30$.

Step7: Solve problem 6

There are 200 quarts of engine oil and 10 quarts are used per day. The number of days the oil will last is $\frac{200}{10}=20$.

Answer:

  1. 12 engines can be repaired.
  2. There are 12 valves in each box.
  3. Each mechanic receives 12 bearings.
  4. 12 sets can be made.
  5. 30 jobs can be completed.
  6. The oil will last 20 days.