Question

two teams are playing tug of war. team a pulls to the right with a force of 450 n. team b pulls to the left with a force of 415 n. what is the net force on the rope, and what is its direction? 35 n to the left 35 n to the right 865 n to the right 865 n to the left

Explanation:

Step1: Define force directions

Let right - ward force be positive, so \(F_A = + 450\ N\) (Team A's force), and left - ward force be negative, so \(F_B=- 415\ N\) (Team B's force).

Step2: Calculate net force

The net force \(F_{net}=F_A + F_B\). Substitute the values: \(F_{net}=450\ N+( - 415\ N)=450 - 415=35\ N\).

Since the net force is positive, the direction of the net force is to the right (because we defined right - ward as positive).

Answer:

35 N to the right