Question

two substances of varying amounts are mixed in four beakers with thermometers. the thermometers are checked every minute for five minutes, and the temperature is recorded in the table.

temperature in beakers over time
time (minutes) | beaker a (°c) | beaker b (°c) | beaker c (°c) | beaker d (°c)
--- | --- | --- | --- | ---
0 | 20 | 20 | 20 | 20
1 | 21 | 19 | 21 | 20
2 | 22 | 18 | 22 | 20
3 | 20 | 18 | 23 | 20
4 | 20 | 17 | 24 | 20
5 | 20 | 16 | 25 | 20

which beaker shows the greatest temperature change over five minutes?

options:
○ c
○ d
○ b
○ a

Explanation:

Step1: Calculate change for Beaker A

Initial temp: \(20^\circ C\), Final temp: \(20^\circ C\). Change: \(|20 - 20| = 0\).

Step2: Calculate change for Beaker B

Initial temp: \(20^\circ C\), Final temp: \(16^\circ C\). Change: \(|16 - 20| = 4\).

Step3: Calculate change for Beaker C

Initial temp: \(20^\circ C\), Final temp: \(25^\circ C\). Change: \(|25 - 20| = 5\).

Step4: Calculate change for Beaker D

Initial temp: \(20^\circ C\), Final temp: \(20^\circ C\). Change: \(|20 - 20| = 0\).

Step5: Compare changes

\(0\) (A), \(4\) (B), \(5\) (C), \(0\) (D). Greatest is \(5\) (Beaker C).

Answer:

C