Question

two bumper cars at an amusement park collide and get stuck together. assuming that the system of the two bumper cars is isolated, what does the conservation of momentum tell us? (hint: pay attention to the directions of the arrows) a. m1v1 + m2v2=(m1 + m2)v b. m1v1 - m2v2=(m1 - m2)v c. m1v1 - m2v2=(m1 + m2)v d. m1v1 + m2v2=(m1 - m2)v

Explanation:

Step1: Define momentum directions

Downward as positive; upward as negative.

Step2: Initial momentum calculation

Initial momentum: \( m_1v_1 - m_2v_2 \) (since \( m_2 \) moves upward).

Step3: Final momentum calculation

Final momentum: \( (m_1 + m_2)v \) (combined mass, downward).

Step4: Apply conservation of momentum

Set initial = final: \( m_1v_1 - m_2v_2 = (m_1 + m_2)v \).

Answer:

C. \( m_1v_1 - m_2v_2 = (m_1 + m_2)v \)