Question

for (y && y) || (x &&!x)
in the truth table?
x y (y && y) (x &&!x) (y && y) || (x &&!x)
t t t
t f ?
f t
f f
true false

Explanation:

Step1: Calculate (y && y)

When y is F (False), (y && y) is F.

Step2: Calculate (x &&!x)

When x is T (True),!x is F, so (x &&!x) is F.

Step3: Calculate (y && y) || (x &&!x)

Using logical OR (||), F || F is F.

Answer:

False