Question

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description: show all you work, including units, on separate paper. follow the \problem solving method\
this final exam is cumulative and covers material from the entire course.
instructions: from the list of choices, select the one best answer.
multiple attempts: not allowed. this test can only be taken once.
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question 18 of 62
1.6 points save answer
a boy throws a rock with an initial velocity of 2.15 m/s at 30.0° above the horizontal. what is the vertical component of the initial speed of the rock?
○ 1.08 m/s
○ 0.565 m/s
○ 0.752 m/s
○ 2.02 m/s

Explanation:

Step1: Recall vertical component formula

The vertical component \( v_y \) of an initial velocity \( v_0 \) at an angle \( \theta \) is given by \( v_y = v_0 \sin\theta \).

Step2: Substitute values

Given \( v_0 = 2.15 \, \text{m/s} \) and \( \theta = 30.0^\circ \). We know that \( \sin(30.0^\circ) = 0.5 \). So, \( v_y = 2.15 \times \sin(30.0^\circ) = 2.15 \times 0.5 \).

Step3: Calculate the result

\( 2.15 \times 0.5 = 1.075 \approx 1.08 \, \text{m/s} \).

Answer:

1.08 m/s (corresponding to the first option: 1.08 m/s)