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question 9
let ( y = f(x) ) be a quadratic function given by ( f(x) = ax^2 + bx + c ).
this function can have exactly one y-intercept.
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○ false
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Step1: Recall y - intercept definition
The y - intercept of a function \(y = f(x)\) is found by setting \(x = 0\) and solving for \(y\). For the quadratic function \(f(x)=ax^{2}+bx + c\), when \(x = 0\), we have \(f(0)=a(0)^{2}+b(0)+c=c\).
Step2: Analyze the result
The value of \(f(0)\) is \(c\), which is a single value (since \(a\), \(b\), and \(c\) are constants for a given quadratic function). So, regardless of the values of \(a\) and \(b\) (as long as \(a
eq0\) for it to be quadratic), when \(x = 0\), there is exactly one value of \(y\) (which is \(c\)). So the function \(y = f(x)=ax^{2}+bx + c\) has exactly one y - intercept.
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