Question

submitting an external tool available dec 8 at 12am - jan 23, 2026 at 11:59pm

x	y
-3	-11
-2	-9
-1	-7
0	-5
1	-3
2	-1
3	1

(and a coordinate plane graph)

Explanation:

Step1: Find the slope

The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \( m=\frac{y_2 - y_1}{x_2 - x_1} \). Let's take two points, say \((-3, -11)\) and \((-2, -9)\). Then \( m=\frac{-9 - (-11)}{-2 - (-3)}=\frac{2}{1} = 2 \).

Step2: Find the equation of the line

Using the slope - intercept form \( y=mx + b \), we know \( m = 2 \). From the point \((0, - 5)\) (when \( x = 0 \), \( y=-5\)), we can see that the y - intercept \( b=-5 \). So the equation of the line is \( y = 2x-5 \).

Step3: Analyze the graph

We can plot the points from the table: \((-3,-11)\), \((-2,-9)\), \((-1,-7)\), \((0, - 5)\), \((1,-3)\), \((2,-1)\), \((3,1)\). When we plot these points, we can see that they lie on a straight line with slope 2 and y - intercept - 5. The point that the cursor is near should also lie on this line. Let's check the x - coordinate of the point near the cursor. From the graph, it seems to be around \( x=-2 \) or \( x=-1 \)? Wait, no, looking at the x - axis, the point is at \( x=-2 \)? Wait, no, the x - coordinate of the point with the cursor: let's see the grid. The x - axis has marks at - 5, - 4, - 3, - 2, - 1, 0, 1, 2, 3, 4, 5. The y - axis has marks from - 10 to 4. The point with the cursor: let's calculate \( y \) when \( x=-2 \): \( y=2\times(-2)-5=-4 - 5=-9 \), but the point in the table at \( x = - 2 \) is \( y=-9 \). Wait, maybe the question is to identify the correct graph or the equation? Wait, the problem is probably to find the equation of the line or identify the graph. Since we have a table of points, we can see that the relationship is linear. The slope is 2 and y - intercept is - 5, so the equation is \( y = 2x-5 \).

Answer:

The equation of the line is \( y = 2x - 5 \) (or if it's about the graph, the graph of the line \( y = 2x-5 \) passes through the given points).