Question

a student connects two aa batteries (each battery is 1.5 volts) in series to light up a light bulb. the circuit has a resistance of 6ω. how much current flows through the circuit?
1a
25a
0.03a
300a

Explanation:

Step1: Calculate the total voltage

Since there are two \(1.5V\) batteries in series, the total voltage \(V = 1.5V+1.5V=3V\)

Step2: Use Ohm's Law \(I=\frac{V}{R}\)

Given \(R = 3\Omega\) and \(V = 3V\), then \(I=\frac{3V}{3\Omega}=1A\)

Answer:

A. \(1A\)