Question

1. a sound wave produced by a clock that is a distance of 515 m away is heard 1.50 s later.

a) what is the speed of sound?
b) the sound wave has a frequency of 426 hz. what is the period?
c) what is the wavelength of the sound wave?

Explanation:

Step1: Calculate the speed of sound

The formula for speed is \(v=\frac{d}{t}\), where \(d = 515\space m\) and \(t=1.50\space s\).

$$v=\frac{515}{1.50}$$

$$v = 343.33\space m/s$$

Step2: Calculate the period

The formula for period \(T\) in terms of frequency \(f\) is \(T=\frac{1}{f}\). Given \(f = 426\space Hz\)

$$T=\frac{1}{426}$$

$$T=2.35\times10^{-3}\space s$$

Step3: Calculate the wavelength

The formula for wavelength \(\lambda\) is \(\lambda=\frac{v}{f}\). We know \(v = 343.33\space m/s\) and \(f = 426\space Hz\)

$$\lambda=\frac{343.33}{426}$$

$$\lambda = 0.806\space m$$

Answer:

a) \(343.33\space m/s\)
b) \(2.35\times10^{-3}\space s\)
c) \(0.806\space m\)