Question

solve using substitution.
9x + y = -19
10x - 3y = 20
(□, □)
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Explanation:

Step1: Solve for y from the first equation

From \(9x + y = -19\), we can express \(y\) in terms of \(x\) as \(y = -19 - 9x\).

Step2: Substitute y into the second equation

Substitute \(y = -19 - 9x\) into \(10x - 3y = 20\). So we have:
\(10x - 3(-19 - 9x)=20\)
First, distribute the -3: \(10x + 57 + 27x = 20\)
Then, combine like terms: \(37x + 57 = 20\)
Subtract 57 from both sides: \(37x = 20 - 57 = -37\)
Divide both sides by 37: \(x = \frac{-37}{37} = -1\)

Step3: Find y using x = -1

Substitute \(x = -1\) into \(y = -19 - 9x\):
\(y = -19 - 9(-1)= -19 + 9 = -10\)

Answer:

\((-1, -10)\)