Question

8.6 solve radical equations (homework)
score: 0/16 answered: 0/16
question 1
find all real solutions:
$sqrt{8x + 2}=-9$
$x =$. (if no solution exists, enter dne)

Explanation:

Step1: Analyze square - root property

The square root of a real - number expression $\sqrt{a}$ (where $a = 8x + 2$ in this case) is defined as $\sqrt{a}\geq0$ for all real values of $x$ such that $a\geq0$. Here, the left - hand side is $\sqrt{8x + 2}$, and the right - hand side is $-9$. Since $\sqrt{8x+2}\geq0$ and $-9\lt0$, there is no real number $x$ that can make the equation $\sqrt{8x + 2}=-9$ true.

Answer:

DNE