Question

solve the following equation for x.
$7x^2 - 112 = 0$
a. $x = -4, x = -4$
b. $x = 4, x = 4$
c. $x = -4, x = 4$
d. $x = 5, x = -5$

Explanation:

Step1: Isolate the quadratic term

Add 112 to both sides: $7x^2 = 112$

Step2: Solve for $x^2$

Divide by 7: $x^2 = 16$

Step3: Take square roots

$x = \pm\sqrt{16} = \pm4$

Answer:

C. x = -4, x = 4