solve the equation.

\4g^2 = 25\

\g = \pm \frac{?}{}\

Question

solve the equation.

\4g^2 = 25\

\g = \pm \frac{?}{}\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Solving Quadratic Equations", "Square Root Property" ], "new_concepts": [], "current_concepts": [ "Solving Quadratic Equations", "Square Root Property" ] } ## Isolate the squared term Using the **Solving Quadratic Equations** knowledge point $$ \begin{aligned} 4g^2 &= 25 \ g^2 &= \frac{25}{4} \end{aligned} $$ ## Apply the square root property Using the **Square Root Property** knowledge point $$ \begin{aligned} g &= \pm \sqrt{\frac{25}{4}} \ g &= \pm \frac{\sqrt{25}}{\sqrt{4}} \ g &= \pm \frac{5}{2} \end{aligned} $$ Solve the equation. $$4g^2 = 25$$ $g = \pm$ $\frac{5}{2}$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Solving Quadratic Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Isolate the squared term

Apply the square root property

Answer: