Question

solve for \\(x\\) in the equation \\(x^2 + 4x - 4 = 8\\).

• \\(x = -6\\) or \\(x = 2\\)
• \\(x = -2 \pm 2\sqrt{2}\\)
• \\(x = -2\\) or \\(x = 6\\)
• \\(x = 2 \pm 2\sqrt{2}\\)

Explanation:

Step1: Write the equation

$$x^2 + 4x - 4 = 8$$

Step2: Subtract 8 from both sides

$$x^2 + 4x - 12 = 0$$

Step3: Factor the quadratic equation

$$(x + 6)(x - 2) = 0$$

Step4: Solve for x

$$x = -6 \text{ or } x = 2$$

Answer:

\(x = -6\) or \(x = 2\)