Question

solve \\((t - 3)^2 = 6\\). the arrow is at a height of \\(48\text{ ft}\\) after approximately s and after s.

Explanation:

Step1: Take the square root

$$t - 3 = \pm\sqrt{6}$$

Step2: Solve for t

$$t = 3 \pm\sqrt{6}$$

Step3: Calculate the first value

$$t \approx 3 - 2.45 = 0.55$$

Step4: Calculate the second value

$$t \approx 3 + 2.45 = 5.45$$

Answer:

The arrow is at a height of 48 ft after approximately 0.55 s and after 5.45 s.