Question

is 4 a solution of $z^2 + 2 = 7 + 3z$?
∘ yes
∘ no
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Explanation:

Step1: Substitute z=4 into left side

Calculate \( z^2 + 2 \) when \( z = 4 \): \( 4^2 + 2 = 16 + 2 = 18 \)

Step2: Substitute z=4 into right side

Calculate \( 7 + 3z \) when \( z = 4 \): \( 7 + 3\times4 = 7 + 12 = 19 \)

Step3: Compare both sides

Left side is 18, right side is 19. Since \( 18
eq 19 \), 4 is not a solution.

Answer:

No