Question

simplify the expression.
$4n + \frac{1}{8} + 8z + \frac{1}{8} + 9n - 3z$
$4n + \frac{1}{8} + 8z + \frac{1}{8} + 9n - 3z = \square$
(use the operation symbols in the math palette as needed. sin

Explanation:

Step1: Combine like terms for \( n \)

Identify terms with \( n \): \( 4n \) and \( 9n \). Add them: \( 4n + 9n = 13n \)

Step2: Combine like terms for \( z \)

Identify terms with \( z \): \( 8z \) and \( -3z \). Add them: \( 8z - 3z = 5z \)

Step3: Combine constant terms

Identify constant terms: \( \frac{1}{8} \) and \( \frac{1}{8} \). Add them: \( \frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4} \)

Step4: Combine all simplified terms

Combine \( 13n \), \( 5z \), and \( \frac{1}{4} \): \( 13n + 5z + \frac{1}{4} \)

Answer:

\( 13n + 5z + \frac{1}{4} \)