QUESTION IMAGE
Question
show your work and circle your answer for the questions below.
- tall pea plants (t) are dominant over short peas (t). cross a pure tall plant with a hybrid plant. what is the chance of having a tall trait appearing in the f1 generation?
- huntingtons disease (h) is inherited dominantly. cross a man who is heterozygous for huntingtons with a normal woman. what is the chance that their offspring will have huntingtons disease?
Step1: Determine the genotypes
For question 10: A pure - tall plant has genotype \(TT\), and a hybrid plant has genotype \(Tt\).
For question 11: A man heterozygous for Huntington's has genotype \(Hh\), and a normal woman has genotype \(hh\).
Step2: Set up Punnett squares
Question 10
| \(T\) | \(T\) | |
|---|---|---|
| \(t\) | \(Tt\) | \(Tt\) |
The genotypes of the offspring are \(TT\) and \(Tt\). Since \(T\) (tall) is dominant, all \(TT\) and \(Tt\) plants are tall. The probability of tall plants is \(\frac{4}{4}=1\) or \(100\%\)
Question 11
| \(H\) | \(h\) | |
|---|---|---|
| \(h\) | \(Hh\) | \(hh\) |
The genotypes of the offspring are \(Hh\) (affected) and \(hh\) (unaffected). The probability of having Huntington's disease (\(Hh\)) is \(\frac{2}{4}=\frac{1}{2}\) or \(50\%\)
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- The chance of having a tall trait in the \(F_1\) generation is \(100\%\)
- The chance that their offspring will have Huntington's disease is \(50\%\)