Question

select the correct answer. ellie is pushing a box of mass 7.0 kilograms with the force of 25 newtons. if the force of friction is 2.6 newtons, what is the value of acceleration of the box?
a. 0.7 meters/second squared
b. 2.6 meters/second squared
c. 3.2 meters/second squared
d. 3.6 meters/second squared

Explanation:

Step1: Calculate net force

The net force $F_{net}$ is the applied force minus the frictional force. Given $F_{applied}=25$ N and $F_{friction} = 2.6$ N. So, $F_{net}=F_{applied}-F_{friction}=25 - 2.6=22.4$ N.

Step2: Use Newton's second - law

Newton's second - law is $F = ma$, where $F$ is the net force, $m$ is the mass and $a$ is the acceleration. We know $m = 7.0$ kg and $F = 22.4$ N. Rearranging for $a$, we get $a=\frac{F}{m}$. Substituting the values, $a=\frac{22.4}{7.0}=3.2$ m/s².

Answer:

C. 3.2 meters/second squared