Question

a satellite orbits the earth at a distance of 6,925,008 meters from the center of the earth. the earth has a mass of 5.972 x 10^24 kilograms. what is the tangential velocity of the satellite in meters per second?

Explanation:

Step1: Write the formula for tangential velocity

The formula for the tangential velocity \(v\) of a satellite in orbit is \(v = \sqrt{\frac{GM}{r}}\), where \(G = 6.674\times10^{- 11}\space Nm^{2}/kg^{2}\) (the gravitational constant), \(M\) is the mass of the Earth, and \(r\) is the distance from the center of the Earth to the satellite.

Step2: Substitute the given values into the formula

We are given \(M = 5.972\times10^{24}\space kg\) and \(r=6925008\space m\).
Substitute these values into the formula:

$$
LATEXBLOCK0
$$

$$v\approx7582\space m/s$$

Answer:

\(7582\)