Question

1. sandy is upgrading her internet service. fast internet charges $60 for installation and $50.45 per month. quick internet has free installation but charges $57.95 per month. write an equation that can be used to find the number of months for which the internet service would cost the same. solve it.

Explanation:

Step1: Define variable and costs

Let \( x \) be the number of months. Fast Internet cost: \( 60 + 50.45x \). Quick Internet cost: \( 57.95x \).

Step2: Set costs equal

Equation: \( 60 + 50.45x = 57.95x \)

Step3: Solve for \( x \)

Subtract \( 50.45x \): \( 60 = 57.95x - 50.45x \)
Simplify: \( 60 = 7.5x \)
Divide by 7.5: \( x = \frac{60}{7.5} = 8 \)

Answer:

Equation: \( 60 + 50.45x = 57.95x \), Solution: \( x = 8 \)