Question

1. round peas are dominant to wrinkled peas. cross a homozygous round pea with a heterozygous pea. what percentage of the offspring will be round?

Explanation:

Step1: Determine the genotypes

Let \(R\) represent the allele for round peas (dominant) and \(r\) represent the allele for wrinkled peas (recessive). A homozygous round pea has the genotype \(RR\), and a heterozygous round pea has the genotype \(Rr\).

Step2: Set up the Punnett square

The cross is \(RR\times Rr\). The gametes from \(RR\) are all \(R\), and the gametes from \(Rr\) are \(R\) and \(r\) in equal proportions.

	\(R\)	\(r\)

Step3: Analyze the genotypes of the offspring

The genotypes of the offspring are \(RR\) and \(Rr\). Both \(RR\) and \(Rr\) will express the round - pea phenotype because \(R\) (round) is dominant.
The proportion of \(RR\) is \(\frac{1}{2}\) and the proportion of \(Rr\) is \(\frac{1}{2}\). The proportion of round - pea offspring is \(\frac{1}{2}+\frac{1}{2}=1\) (or \(100\%\))

Answer:

\(100\%\)