Question

rewrite the following polynomial in standard form.
\\(\frac{1}{10}x^2 + 10 - 3x\\)

Explanation:

Step1: Recall standard form of polynomial

A polynomial in standard form is written in descending order of the exponents of the variable. The general form for a quadratic polynomial (degree 2) is \(ax^{2}+bx + c\), where \(a
eq0\), and the terms are arranged from the highest power of \(x\) to the lowest.

Step2: Rearrange the given polynomial

The given polynomial is \(\frac{1}{10}x^{2}+10 - 3x\). We need to rearrange the terms so that the exponents of \(x\) are in descending order. The term with \(x^{2}\) is \(\frac{1}{10}x^{2}\), the term with \(x\) is \(- 3x\) (we move the \(-3x\) from the end to the middle), and the constant term is \(10\). So when we rearrange, we get \(\frac{1}{10}x^{2}-3x + 10\).

Answer:

\(\frac{1}{10}x^{2}-3x + 10\)