Question

question what is the volume of a cylinder with a height of 9.2 ft and a base with a radius of 3.9 ft, to the nearest tenth of a cubic foot? answer attempt 1 out of 2

Explanation:

Step1: Recall volume formula

The volume formula for a cylinder is $V=\pi r^{2}h$, where $r$ is the radius and $h$ is the height.

Step2: Substitute given values

Given $r = 3.9$ ft and $h=9.2$ ft. Substitute into the formula: $V=\pi\times(3.9)^{2}\times9.2$.
First, calculate $(3.9)^{2}=3.9\times3.9 = 15.21$. Then $V=\pi\times15.21\times9.2=15.21\times9.2\pi=139.932\pi$.

Step3: Calculate the value

Using $\pi\approx3.14159$, $V\approx139.932\times3.14159\approx439.6$.

Answer:

$439.6$