Question

question
use arrow notation to describe the local behavior for the reciprocal squared function, shown in the graph below:
f(x) = 1/x²

Explanation:

Step1: Analyze left - hand behavior near x = 0

As $x$ approaches $0$ from the left side ($x\to0^{-}$), the function values increase without bound. So, $f(x)\to+\infty$ as $x\to0^{-}$.

Step2: Analyze right - hand behavior near x = 0

As $x$ approaches $0$ from the right side ($x\to0^{+}$), the function values also increase without bound. So, $f(x)\to+\infty$ as $x\to0^{+}$.

Answer:

As $x\to0^{-}, f(x)\to+\infty$; as $x\to0^{+}, f(x)\to+\infty$