Question

this question has two parts. first, answer part a. then, answer part b.
part a
a. write the given equation in slope - intercept form.
5x + 10y = 20
part b
b. identify the slope m and the y - intercept b. enter the slope and then the y - intercept, separated by a comma. for example: 2, 4

Explanation:

Part A Step1: Recall slope - intercept form

The slope - intercept form of a linear equation is \(y=mx + b\), where \(m\) is the slope and \(b\) is the \(y\) - intercept. We need to solve the equation \(5x + 10y=20\) for \(y\).
First, subtract \(5x\) from both sides of the equation: \(10y=- 5x + 20\).

Part A Step2: Solve for \(y\)

Divide each term in the equation \(10y=-5x + 20\) by \(10\).
\(y=\frac{-5x}{10}+\frac{20}{10}\), which simplifies to \(y =-\frac{1}{2}x + 2\).

Part B Step1: Identify \(m\) and \(b\)

From the slope - intercept form \(y=mx + b\) and our equation \(y =-\frac{1}{2}x+2\), we can see that the slope \(m=-\frac{1}{2}\) and the \(y\) - intercept \(b = 2\).

Answer:

Part A: \(y=-\frac{1}{2}x + 2\)
Part B: \(-\frac{1}{2},2\)