Question

question solve for all values of x by factoring. $x^2 + 6x - 41 = 6x - 5$ answer attempt 1 out of 2

Explanation:

Step1: Simplify the equation

Subtract $6x - 5$ from both sides:
$x^2 + 6x - 41 - (6x - 5) = 0$
$x^2 + 6x - 41 - 6x + 5 = 0$
$x^2 - 36 = 0$

Step2: Factor the difference of squares

Recognize $x^2 - 36$ as $a^2 - b^2 = (a-b)(a+b)$:
$(x - 6)(x + 6) = 0$

Step3: Solve for x

Set each factor equal to 0:
$x - 6 = 0$ or $x + 6 = 0$

Answer:

$x = 6$ and $x = -6$