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question
simplify \\(\sqrt{25x^{12}}\\) completely given \\(x > 0\\).
answer attempt 1 out of 5
Step1: Apply square root property
We know that $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ (for $a\geq0,b\geq0$). So, $\sqrt{25x^{12}}=\sqrt{25}\cdot\sqrt{x^{12}}$.
Step2: Simplify each square root
For $\sqrt{25}$, since $5^2 = 25$, we have $\sqrt{25}=5$. For $\sqrt{x^{12}}$, using the property $\sqrt{x^n}=x^{\frac{n}{2}}$ (when $x>0$), here $n = 12$, so $\sqrt{x^{12}}=x^{\frac{12}{2}}=x^6$.
Step3: Combine the results
Multiply the two simplified square roots: $5\cdot x^6 = 5x^6$.
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$5x^6$