Question

question 3 1 pts which of the following is not a means of transporting oxygen in the blood? as oxyhemoglobin combined with the bicarbonate ion (hco3-) dissolved in the plasma all of the above are used to transport oxygen in the blood. question 4 1 pts the function of the vibrissae in the vestibule is to: provide a large, mucus-covered surface area over which air must pass before reaching the pharynx. provide an initial \filter\ to screen particulate matter from air that is entering the system. produce copious quantities of mucus. serve as resonating chambers for speech. question 5 1 pts which of the following is not a true statement? when the diaphragm relaxes, it returns to a domelike shape. when the diaphragm contracts, it pulls the floor of the thoracic cavity downward. changes in thorax size bring about inspiration and expiration. raising the ribs decreases the depth and width of the thorax.

Explanation:

Question 3

• Oxyhemoglobin (\(HbO_2\)) is the form in which oxygen binds to hemoglobin for transport.
• A small amount of oxygen is dissolved in plasma.
• Bicarbonate ion (\(HCO_3^-\)) is mainly involved in carbon dioxide transport (as part of the bicarbonate buffer system for \(CO_2\) transport, not oxygen).

• Vibrissae are nasal hairs. Their main function is to act as an initial filter, trapping large particulate matter in the air we inhale.
• The large mucus - covered surface area for air passage is more related to the nasal mucosa. Mucus is produced by goblet cells and mucous glands, not vibrissae. Resonating chambers for speech are the sinuses.

• When the diaphragm relaxes, it does return to a domelike shape (exhalation phase).
• When the diaphragm contracts, it flattens (pulls the floor of the thoracic cavity downward, increasing thoracic volume for inhalation).
• Changes in thorax size (due to diaphragm and intercostal muscle movements) do cause inspiration (enlarged thorax) and expiration (reduced thorax).
• Raising the ribs (by external intercostal muscles) actually increases the depth and width of the thorax (during inhalation).

Answer:

Combined with the bicarbonate ion (\(HCO_3^-\))

Question 4